ok.. I get out of school.. June .. umm.. between 15-17th ? Not 100% sure... I will be honest with you.. My grades are shit... I don't know why I havn't been trying.. Just last semester sucked.. but I passed.. Well it being May 2nd now.. I realize I only have a month and a few weeks of school left.. and I need to pass... I'm doing all my world history assiments.. in a few minutes.. and some of the math I got... If from tomorrow on.. If i started doign all my hw and class work... Could I pass? I dont know.. Sometimes I just get this lazyness streak for a semester ( every couple of years ) But I think I got to deep into this one.. So will my plan of starting to do all HW and CW work? I'm in HS... or any other ideas besides not screwing off in the first place... Any other ideas? Thanks guys
One of my most problemed classes is math... I don't get it all... Is there a website that has ALL the terms.. and solutions... and like a positive + a negative = ?? w/e it is... Here is a problem off some of my current work.. Its says solve :
5/4 - 5/9 = X/12 here is another 9/X-3 = 2x/X-3 .... There supposed to be one on top.. one of bottom.. but don't know how to do it on the comp.... I do not get that math at all..
5/4 - 5/9 = X/12 if I remember right, you are trying to make it so the variable is 'alone' and equals something. First you must find a common denominator..which would be 36. multiply the first problem by 9 (because4 x 9=36) the second by 4 and the third by 3. now you have: 45/36-20/36=3x/36. now you can subtract and you are left with: 25/36=3x/36..to get the 36 over..multiply both sides by 36. you now have: 25=3x (the 36 cancel on both sides. since its multiplication you would divide 3 by both sides and you are left with: 25/3=x ...lol hope this helps some?
I love math. I used to teach the seniors how to do math when I was a Junior. As soon as I find my luck calculator I'll post on how to do it "MY WAY". Where the hell did that damn thing go.
rummages through old school supplies
Ugh, my sister has it and she lives upstate. Alright, I'll try to explain a PART of how I do it my way.
First, you have to find yourself a checkpoint. Meaning, plugging in your final answer, in this case being 'X', both sides should equal the same decimal number.
So, in your (scientific) calculator you would type in:
( 5 / 4 ) - ( 5 / 9 )
Hit the ' = ' and you will get your checkpoint decimal number.
In this case your checkpoint number is something like .694444444444 repeating
Now, you can go the regular way of doing things. Make the denominators the same on both sides. They all have to be divisible by the same number, and since 12 is the biggest in this situation, you would multiply that until you find a number that they all can evenly divide into. In number terms.
12 * A = Y
9 * B = Y
4 * C = Y
They all evenly go into 36. So....
12 * A = 36 --------> A = 3
9 * B = 36 --------> B = 4
4 * C = 36 --------> C = 9
Now, let's look at the original problem.
( 5C / 36 ) - ( 5B / 36 ) = AX/36 -----> plug in letters
( 45 / 36 ) - ( 20 / 36 ) = 3x/36 -----> find out parentheses
( 25 / 36 ) = 3x/36
Now you see that the only difference between the two is the numerators. How many times does 3 go into 25?
25 / 3 = 8.33333333 repeating or 8 and one third (1/3)
And that's the answer, but now you have to use your checkpoint number to ensure that the answer you got is correct you and didn't mess up anywhere.
If 'X' = 8.3333 repeating
Then 8.333333333 / 12 should equal your checkpoint number
punch it in...............
it equals your checkpoint number
( .6944444444) , it's correct!
Ugh, yeah.... i realize now that could be quite confusing. I could do it on paper, scan it, and send it to you through e-mail FaBMX, if that will help. It should be a lot easier to figure out then.